Correct Answer!

We use the :

lim
n® ¥ 
| an+1|
| an|
=
lim
n® ¥ 
3n-1-1
3n-1

  =  
 

lim
n®¥ 
1/3-3-n
1-3-n
= 1
3
< 1
Thus, the series .

Note that this problem could also be solved by