Correct Answer!

Our series does converge absolutely. Also, the could be used here.

We hope that you properly chose the series for comparison. An example of appropriate comparison here would be:
1
2n-1
³ 1
3n-1-1
.
Note that the most obvious series to compare our series to, i.e.
¥
å
n = 2 
1
3n-1
does not work. Because of the inequality
1
3n-1
£ 1
3n-1-1
,
convergence of
¥
å
n = 2 
1
3n-1
does not imply convergence of
¥
å
n = 2 
1
3n-1 - 1
.

Note that this problem could also be solved using